BB(6) hunt

Decision queue

0 open calls · 24 answered · built 2026-10-16 13:29

Each card pre-selects Claude's recommendation (marked recommended). Change what you disagree with, add a note if you like, then press Copy my answers at the bottom and paste the text to Claude. “Not now” leaves a machine out. Your choices stay in this browser until you reset them, also across rebuilds of this page (a card whose question changed starts fresh).

Already answered (24)your answer is on file; change it only if you changed your mind

space-time diagram from the blank tape, steps 0 to 10,000
1RB0LC_1LA0RE_0RD1LF_1LC1LB_0LD0RB_0LA---#1sheet Structural counter + counter ≠ ours Two coupled binary counters: drifting-defect digit counter (right) + edge bit counter (left) · med confidence
⚠Cryptid candidateinformal proofasked Oct 10pageproof.mddecision.jsonbbchallenge ↗

Why it is here Priority call (cryptid protocol). STUCK at informal_proof with cryptid_flag set: the absorption-safety lemma Safe is not inductive, and no strengthening X is known.

Stop proof work on #1 and file it as a cryptid candidate (rules written out, Rocq rule reduction later), or spend another stage searching for the missing invariant clause X?

✓ you said stop · Stop: mark CRYPTID_CANDIDATE; Rocq rule reduction later, low priority · Oct 10
“Dennis: go with all recommendations (2026-10-10)”

Options

Effort if yes No compute now. When scheduled, the Rocq rule reduction takes about 1-2 stages (2-4 h), because L and the ABS rules must become proved multisteps first.

Why Claude recommends stop

This is the case the cryptid protocol covers: formalize the rules, flag, and stop. Non-halting comes down to whether a coupled counter system avoids a sparse target set. The left counter u must miss O(1)-wide unsafe values at about one leading-O birth per doubling of Delta. The trajectory came within 2 sweeps of a configuration that is verified to halt (step 86,265). Later margins are only 7-13% of Delta, and the band edge sits on an unsafe point, so the obvious margin route is already closed. Heuristically the machine never halts, but no structural reason is known. Another search stage has poor odds, and stopping frees the budget for machines with validated mechanisms. The rule table itself is clean (1,096,578 sweeps exact to 1e10), so it is worth keeping as the write-up.

Evidence
  • proof proof.md 3.3-3.4: Safe(w, 2g-1-d_1) can be decided on any single configuration, but it is not inductive. Configurations satisfying every proved clause still halt, e.g. Dep(1O100; 1; 11; 2,0) at step 940, and 85 of 323 random starts failing only this clause halted within 2e6 steps. proof.md
  • near-halt Step 86,265: Dep(O111000; 1; 111100; 9,4,2,0,0,0). The same configuration two sweeps later (word O111100) halts 18,861 steps on (unsafe_probe.c). unsafe_probe.c
  • data At marker-free ABS0 events, u/Delta fills [1.6066, 2.0006], and the 3/4 unsafe point is at 2.0. Margins at the five ABS0 events with a marker (to 1e10 sweeps): 2 sweeps, then 7-13% of Delta. proof.md
  • Fig 1 · Hub map: one row per right sweep
    Card Fig 1: the hub map, one row per right sweep, showing both counters.Card Fig 1: the hub map, one row per right sweep, showing both counters.
    customStart mid-run: step 7,400,830Rows one row per hub = start of each right sweepWindow cells -412..105, 1 px = 0.5 cellsColors 1 0 head (E) 1s between the head and the first two 10110 blocks one 10110 background block digit 110 (=1) digit 100 (=0) 1s of the right-end tail 11 blank
    Rows: (state E, taken 6 cells after the head turns right): 1,056 rows, steps 7,400,830 to 8,747,651, unevenly spaced (22 to 2,614 steps apart, median 1,272) · Window: each cell 2 px wide; each row 1 px tall · Colors: each row recoloured from its parsed hub: left of the head (10 W σ); lavender: normally the 110 right after the head; gray: 5 cells drawn flat
2 more items (past the contract's 4)
  • rules The rules are exact. GEN/ABS1/ABS0 match all 1,096,578 sweeps from step 2,000 to 1e10, random validation passes 8,540/8,540, and check_proof.py reports SUMMARY PASS 36/36. deepen.json
  • status status.json: STUCK at informal_proof, cryptid_flag true, next = Dennis decides: stop or continue. status.json
decision.json: 7 warnings
  • rationale: about 8 lines (contract: <= 3)
  • evidence[0].kind: 'proof' is not one of figure, fact, link (shown as a fact, tagged 'proof')
  • evidence[1].kind: 'near-halt' is not one of figure, fact, link (shown as a fact, tagged 'near-halt')
  • evidence[2].kind: 'data' is not one of figure, fact, link (shown as a fact, tagged 'data')
  • evidence[3].kind: 'rules' is not one of figure, fact, link (shown as a fact, tagged 'rules')
  • evidence[4].kind: 'status' is not one of figure, fact, link (shown as a fact, tagged 'status')
  • evidence: 6 items (contract: <= 4; the extra ones are folded)

check: python3 -B tools/decisions.py --lint '1RB0LC_1LA0RE_0RD1LF_1LC1LB_0LD0RB_0LA---'

space-time diagram from the blank tape, steps 0 to 10,000
1RB1LC_1RC---_1LD1LC_1RE0LC_1RF0RE_1RA0RD#6Structural counter + chaotic edge (sheet) · ours adds: drifting defect groups (hierarchical counter) fed by a chaotic right edge · med confidence
⚠Cryptid candidatedeepen2asked Oct 10pagedecision.jsonbbchallenge ↗

Why it is here Priority call on a CRYPTID_CANDIDATE. Halting reduces exactly to a 5-stage chain, and the phases of its stages behave like unforced coin flips.

Stop work on #6 and its twin #27: keep #6 flagged CRYPTID_CANDIDATE and park proof work, rather than spend a stage decoding the mixed zone?

✓ you said stop · Stop: keep CRYPTID_CANDIDATE and park · Oct 10
“Dennis: go with all recommendations (2026-10-10)”

Options

Effort if yes None now. Later, at low priority alongside #5: about one stage for the cryptid write-up (the coin-model heuristic and the halting-chain reduction).

Why Claude recommends stop

Round 2 made the halting condition exact. The machine halts only when the cluster 11.01.00 meets arrivals in the phases x,E,x,x,E. That sequence halts in 60 of 60 instances, and every other phase prefix dissolves the cluster harmlessly. Seeds of this chain keep forming: 11 by 2.45e10 steps, about 0.7 per doubling. Stages 2-5 read only the left context, and their phases match the generic rates seen anywhere on the tape (about 50%, 35%, 13% and 50%). Two candidate invariants were ruled out (a global phase gauge and gap mod 4), and the 70 cells left of each seed differ in every seed. A non-halting proof would need hidden structure that the data do not show. Under the coin model the machine halts only around 2^100 steps or later, so neither a proof nor a halting search is in reach. This is the obstacle the cryptid protocol is for. Another stage would gain little: 11 seeds are too few to test events that happen 1% of the time.

Evidence
  • validation The halting chain on cluster 11.01.00: x,E,x,x,E halts 60/60, and x,E,x,x,x ends in a safe 1^5 60/60. All 30 phase prefixes of length 1-4 give a single outcome each (40 instances each). deepen2_chainval.py
  • sim Direct simulation to about 4e10 steps found 11 seeds (steps 1.93e6 to 2.45e10). Stage 2 was E in 4 of 10. Seed #3 is the near miss at step 12,975,111, which got through x,E,x. deepen2_chain_seeds_4e10.txt
  • analysis Generic next-arrival rates (3e8 and 1e9 runs) are 49.7%, 34.7% and 12.7%, which match the seeds; nothing forces them. The coin model gives about a 1% halt chance per seed. deepen.json
  • Fig 2 · Right edge pinned, defects only
    Fig 2: the dense band at the right edge that emits defects.Fig 2: the dense band at the right edge that emits defects.
    customStart blankRows the start, then one per new rightmost cellWindow cells -1,599..0, 1 px = 2 cellsColors at least one defect (00 or 11) among the pixel's 2 cells clean 0101... run not yet visited
    Rows: (2,819 rows, steps 0..969,848,428; no new right cell from then to 1e9); not evenly spaced in time · Window: counted from the right edge (each row's rightmost visited cell is 0, pinned to the last column; it is absolute cell 2,818 in the last row) · Colors: head not drawn; Each slanted line = a defect drifting left, away from the edge; the dense band at the right = the chaotic edge zone
4 more items (past the contract's 4)
  • analysis Invariants ruled out. Phase gauge: takes all 4 values in 5,175 of 5,180 wall cycles. Gap mod 4: k = 0 mod 4 in 10,472 cases and k = 2 mod 4 in 76, and the seeds are among the k = 2 exceptions. notes.md
  • validation The solid part: the left counter G16 (32/32, locked from step 190,860 and matching on 193/193 visits) and the 1,440/1,440 head/defect interaction table. notes.md
  • sim No halt to 1e11 steps (C core).
  • risk Against stopping: the mixed zone is undecoded, so hidden (for example 2-automatic) structure coming from the counter is not excluded. That is what the 'decode' option would look for.
decision.json: 9 warnings
  • rationale: about 9 lines (contract: <= 3)
  • evidence[0].kind: 'validation' is not one of figure, fact, link (shown as a fact, tagged 'validation')
  • evidence[1].kind: 'sim' is not one of figure, fact, link (shown as a fact, tagged 'sim')
  • evidence[2].kind: 'analysis' is not one of figure, fact, link (shown as a fact, tagged 'analysis')
  • evidence[3].kind: 'analysis' is not one of figure, fact, link (shown as a fact, tagged 'analysis')
  • evidence[4].kind: 'validation' is not one of figure, fact, link (shown as a fact, tagged 'validation')
  • evidence[5].kind: 'sim' is not one of figure, fact, link (shown as a fact, tagged 'sim')
  • evidence[6].kind: 'risk' is not one of figure, fact, link (shown as a fact, tagged 'risk')
  • evidence: 8 items (contract: <= 4; the extra ones are folded)

check: python3 -B tools/decisions.py --lint '1RB1LC_1RC---_1LD1LC_1RE0LC_1RF0RE_1RA0RD'

space-time diagram from the blank tape, steps 0 to 10,000
1RB0LD_0RC1RA_1RD1RF_1LA0LE_0RA0LC_0RA---#9sheet Shift-overflow structural counter ≠ ours Shift-overflow counter: base-4 digit blocks in a bouncer, plus a one-time reset that leaves walls · med confidence
▲Stuckinduct parkedasked Oct 10pagedecision.jsonbbchallenge ↗

Why it is here Parked by the stop rule: the left zone is safe in every generation computed but neither stable nor growing. A cheap way back in exists, so this is a priority call.

Keep #9 parked, as the stop rule says, or fund one stage to test whether its left zone settles into a 2-cycle across generations?

✓ you said park · Keep parked · Oct 11
“Dennis: go with recommendations (2026-10-11)”

Options

Effort if yes One stage (about 2 h). If the 2-cycle holds: proof.md, then exhaustive tile checks of both tables and a large formalization over several stages.

Why Claude recommends park

Stop rule hit: left-zone size went 50, 168, 96, 128, 212 cells over gens 2-6. Every zone tested is safe (0/80 nested); gens g and g-2 agree on 53, 91, 99 cells. A 2-cycle is plausible but unshown; other machines are closer to a kill.

Evidence
  • Window map from the real gen-1 window reproduces all 12 real gen-2 left-zone events (6/6 runs, 11-12 blocks). val12seq.json
  • Predicted left zones, gens 3-6: raw prefix 168, 96, 128, 212 cells; gens g and g-2 agree on 53, 91, 99 cells. iter2_8_10_g7.json
  • Capacity: gen-3 zone 0/80 and gen-4 zone 0/80 nested events (real gen-2 zone: 22/200 nested DA). tcap_g3_R2.json
  • Fig 3 · After the reset: left quarter to 1e9
    Fig 3: digit lines cross the reset walls without bending.Fig 3: digit lines cross the reset walls without bending.
    customStart blankRows one row per 6th sweep endWindow cells -40..13,559, 1 px = 8 cellsColors shift 0..7 block that is not a copy of P not visited yet
    Rows: (head at the right edge in state D): 2,177 rows, steps 527..999,316,836. Not equal time: rows ~1,000 steps apart at the top, ~950,000 at the bottom, and between rows 363 and 364 (from the top) 8.1M steps are skipped (29,646,275 -> 37,788,160: the reset) · Window: the left quarter of the tape, an exact crop of img/phase_1e9.png; all 7 walls left by the reset (cells ~190..8,750) are in it, and cells 13,560..52,247 (not shown) hold only the newest digit runs · Colors: away from digits the tape repeats the 8-cell word P = 11111010, and colour = how P is shifted in that 8-cell block (red, orange, yellow, green, cyan, blue, purple, magenta = shift 0..7); colour edge = a digit block (6 cells: colour steps back 2, e.g. green -> orange) or a wall X = 11 (2 cells: colour steps forward 2)
space-time diagram from the blank tape, steps 0 to 10,000
1RB0LE_1LC1RD_1LA0RB_1RC1RB_1LF0LC_---0RC#13Bouncer + Chaotic Edge (sheet) · ours adds: translating period-10 bouncer feeding a 1-sided chaotic edge map · high confidence
▲Stuckinformal proofasked Oct 10pageproof.mddecision.jsonbbchallenge ↗

Why it is here Priority call. STUCK at informal_proof: the edge lemma (E') is the whole difficulty, and every remaining route is expensive with unknown odds.

Continue investing in the edge lemma (E') or park the machine?

✓ you said park · Park: STUCK at informal_proof, keep proof.md as the conditional reduction · Oct 10
“Dennis: go with all recommendations (2026-10-10)”

Options

Effort if yes None now. Status stays STUCK (informal_proof) with the priority call answered. Reopening later costs nothing beyond running whatever new tool exists by then.

Why Claude recommends park

The tail D is chaotic. It does not repeat in 5.5e6 cycles, its k-factor counts grow about 1.6^k without saturating, and 120 cycles show 3,786 distinct per-cell crossing sequences. Every regular candidate tried so far has failed: SFT_k invariants are refuted with verified chains for every k <= 36, plain n-gram CPS does not close (whole machine n <= 26, edge system n <= 24), and CTL62 searches ran out of memory with no verdict. Nobody knows whether any regular invariant exists, and the cheapest remaining route costs days with unknown odds. The obstacle is not arithmetic, but for proof purposes it behaves like a cryptid: no structure has been found to build an invariant on. The budget does more on machines with validated mechanisms, and the conditional reduction keeps this work reusable.

Evidence
  • proof proof.md 6.4: SFT_k refuted for k <= 22 by sampling and for k = 24-36 by verified chains. Plain CPS does not close. Two CTL62 Nsolve_cert runs reached about 10 GB within 5 min and were killed with no verdict. proof.md
  • refutation Refutation chains for k = 24, 26, 28, 30, 32, 36, each re-checked in pure Python by scripts/edge_sft/verify_refutations.py. refute_k36.txt
  • data Orbit to 5.5e6 cycles: no break, no halt, no repeated D, |D| in [144, 564] with no drift, deeper cells chaotic (proof.md 6.3). proof.md
  • Fig 1 · One row per bounce, from a built tape
    Card Fig 1: one row per bounce. Regular bulk and junction, all the disorder in the tail.Card Fig 1: one row per bounce. Regular bulk and junction, all the disorder in the tail.
    bbchallenge-defaultStart constructed: 0∞ <A (1101101101)20 X0 D0 0∞Rows left recordsWindow cells -320..725, 1 px = 0.5 cellsColors 1 0 or never visited head just moved right/left
    Start: X0 = the fixed 54-cell junction; D0 = the real 261-cell tail at step 784,041, where the real bulk is a = 59, not 20 · Rows: the start, then one row per new leftmost cell = one row per bounce (321 rows, steps 0..1,200,000; 7 rows = one probe cycle) · Window: each cell is 2x2 px; cell 0 = the cell the head reads at the start
2 more items (past the contract's 4)
  • rules Everything except (E') passes check_proof.py: RS/LS/WS/WE and J1-J6 with unknown context, B1-B6, IFACE (the same 32 crossings on 3,000 cycles), INIT at 784,041 steps. check_proof.py
  • status status.json: STUCK, informal_proof, priority_call = continue on (E') or park. status.json
decision.json: 7 warnings
  • rationale: about 8 lines (contract: <= 3)
  • evidence[0].kind: 'proof' is not one of figure, fact, link (shown as a fact, tagged 'proof')
  • evidence[1].kind: 'refutation' is not one of figure, fact, link (shown as a fact, tagged 'refutation')
  • evidence[2].kind: 'data' is not one of figure, fact, link (shown as a fact, tagged 'data')
  • evidence[3].kind: 'rules' is not one of figure, fact, link (shown as a fact, tagged 'rules')
  • evidence[4].kind: 'status' is not one of figure, fact, link (shown as a fact, tagged 'status')
  • evidence: 6 items (contract: <= 4; the extra ones are folded)

check: python3 -B tools/decisions.py --lint '1RB0LE_1LC1RD_1LA0RB_1RC1RB_1LF0LC_---0RC'

space-time diagram from the blank tape, steps 0 to 10,000
1RB0LF_0RC0RB_1LC1LD_1RE0RD_---0RA_1LA0LF#17sheet Unknown ≠ ours Self-similar multi-wall bouncer (x3 epochs) · med confidence
▲Stuckdeepen2asked Oct 10pagedecision.jsonbbchallenge ↗

Why it is here Priority call: deepen 2 marked #17 STUCK with no proof route in reach. The only route left is a multi-day project that needs your funding.

#17's cheap proof routes are closed: epoch induction is blocked on the tail, and no regular closed language exists at the sizes tried. Park it, or fund a multi-day particle-level simulator plus an invariant on particle sequences?

✓ you said park · Park #17 as STUCK · Oct 10
“Dennis: go with all recommendations (2026-10-10)”

Options

Effort if yes About 10 minutes: confirm STUCK in status.json with 'parked by Dennis' and update STATUS.md. No compute.

Why Claude recommends park

The micro rules and the left recursion are exact: a_n = 171*3^n - 3 predicted epoch 5 before it was simulated. Halting reduces to one local pattern, and the machine has come near it only at the right edge (6 D1 events, all in E0 and E3, all reading 1). But the tail is a fossil-processing particle system whose catalogue keeps growing (363 types, with new ones in E7 and E8), and E8 rebuilt the right end without its 1^k run. Both cheap routes failed: plain CPS up to n = 20 and parity CPS up to n = 14 both give abstract HALT, and bulk saturation fails after E4. What remains is open-ended (several days) with no template, while four machines in this queue each need one well-defined lemma. Parking loses nothing, since the evidence is written up. With no halt to 4.31e13 and no near-halt ever seen in the bulk, it is not a promising halting candidate either.

Evidence
  • rules Epoch map P(a,c,T) -> P(3a+6, 3a+c+2, T') 34/34, including 4 swapped-in tails; burst cycle 420/420; slow-phase cycle 86/86. The closed form a_n = 171*3^n - 3 predicted epoch 5 before it was simulated. notes.md
  • rules Crossing lemma checked on all 931,918 sweeps to 3.54e10. Halting lemma (the machine halts iff 1 0 0 <F 0 0 (0 0 | 1 0 0) occurs) matched 7,886/7,888 random halts after step 40; the 2 misses come from the random start. deepen.json
  • data No halt to 3.3e11 by direct simulation (exactly 6 D1 near-halts, none after step 2.497e9), and none to 4.31e13 by Quick_Sim, cross-checked cell for cell. The E8 right-end rebuild was re-run at cell level with 0 D1. longrun_3.3e11.txt
  • Tail particles at each epoch start, placed by distance from the right end: grey = fossil suffix unchanged since the previous start, blue = rewritten.Tail particles at each epoch start, placed by distance from the right end: grey = fossil suffix unchanged since the previous start, blue = rewritten.
2 more items (past the contract's 4)
  • open The tail is a particle system with a growing catalogue: 363 particle types over 29,643 left-edge visits, with new ones in E7 and E8. The right end is rewritten only in E0, E3, E4, E7 and E8, which fits epoch = 0 or 3 mod 4 (a hypothesis from 9 epochs). tailmap.txt
  • probe Invariants tried, all failed: plain n-gram CPS (abstract HALT for n = 2..12, 16, 18, 20), parity-aware CPS (n = 3..14), and the static forbidden factor 0011 (writes create it 744,280 times to 4e9). deepen.json
decision.json: 9 warnings
  • question: 2 sentences (contract: one)
  • rationale: about 8 lines (contract: <= 3)
  • evidence[0].kind: 'rules' is not one of figure, fact, link (shown as a fact, tagged 'rules')
  • evidence[1].kind: 'rules' is not one of figure, fact, link (shown as a fact, tagged 'rules')
  • evidence[2].kind: 'data' is not one of figure, fact, link (shown as a fact, tagged 'data')
  • evidence[3].kind: 'open' is not one of figure, fact, link (shown as a fact, tagged 'open')
  • evidence[4].kind: 'probe' is not one of figure, fact, link (shown as a fact, tagged 'probe')
  • evidence: 6 items (contract: <= 4; the extra ones are folded)
  • evidence[5]: 'img/deepen2_tail_fossils.svg' is not an observe.json diagram, so it has no label (use a primary diagram)

check: python3 -B tools/decisions.py --lint '1RB0LF_0RC0RB_1LC1LD_1RE0RD_---0RA_1LA0LF'

space-time diagram from the blank tape, steps 0 to 10,000
1RB1RF_1RC---_1RD0RD_1LE1RC_1RA1LE_1RE0LF#19sheet Shift-overflow structural counter ≠ ours Base-4 bouncer counter: separators between growing 6-cell zones are the digits · med confidence
▲Stuckdeepen2asked Oct 10pagedecision.jsonbbchallenge ↗

Why it is here Priority call with mechanism confidence low. The base-4 counter is validated, but the machine turned out to be multi-epoch, and the overflow/rebuild rule and the epoch recursion are open.

Park #19, rather than fund a stage on its overflow/rebuild rule?

✓ you said park · Park (STUCK at deepen2) · Oct 10
“Dennis: go with all recommendations (2026-10-10)”

Options

Effort if yes None: 0 agent hours and 0 processes. Status becomes STUCK (parked), with the deepen-2 findings as the re-entry point.

Why Claude recommends park

Within an epoch, #19 is solved in practice. One uniform digit rule explains 119,956 of 120,091 trips to 1e11 steps, the closed-form fast-forward reproduces the real run, and all 72 top events to trip 13.5e6 behave. But round 2 found where the epoch ends, at about 1.27e15 steps. There, a recoding pass rewrites the whole tape. Its time is quadratic in zone size (about 1e16 steps at the real sizes). It splits zones into pieces whose sizes and number depend on the parity of m (S = 200, 202, 204 give a different structure from 201 and 203). A new counter then grows on top of the recoded tape. A proof would need three things: a rule for how every zone is recoded, an epoch-to-epoch recursion, and an invariant that survives parity-dependent recodings of zones millions of blocks long. That is new work several stages deep, and parity splits on such large numbers are the warning sign the cryptid protocol names. No cheap compute settles it, because the next epoch lies far beyond 1e16 steps. Parking keeps the budget for machines with validated mechanisms. Revisit if R5's overflow run, or another shift-overflow machine, yields a reusable epoch-recursion argument.

Evidence
  • validation Uniform digit rule (types A/B, 4 states each): 119,956 of 120,091 trip transitions to 1e11 steps match token by token. The other 135 are identified start-up, left-end and top-region events. counter_trace_1e11.json
  • sim The topsim closed-form fast-forward reproduces all 16 round-1 events and 3 full-size K=9 events. It finds 72 top events up to trip 13,539,937, and none halts. topsim_events_to_13539937.log
  • analysis Epoch overflow at trip 13,539,937 (about 1.27e15 steps): the carry crosses the top region, the sweep makes the first left record since 1.8e8, and the return pass recodes the whole tape. pre_overflow_13539937.json
  • Fig 2 · One row per round trip, 452 trips
    Fig 2: the base-4 turn-back pattern, one row per round trip.Fig 2: the base-4 turn-back pattern, one row per round trip.
    customStart blankRows one per round trip of the headWindow cells -68..900, 1 px = 1 cellColors 1/0 on cells this trip reached 1/0 on cells it did not reach the turn-back cell not yet visited
    Rows: (it leaves the right end, turns back, returns to within 120 cells of the right end), drawn at the return: 452 trips, steps 24,389..1,994,475 (1 row = 4 px tall); not evenly spaced in time · Window: the right part of the tape, up to cell 2,185 at the end, is cut off: every trip reaches it · Colors: red: deepest point; The red diagonal is S0 (3 trips in 4 turn there); every 4th trip goes on to S1, every 16th to S2, every 64th deeper still
3 more items (past the contract's 4)
  • risk Capped rebuilds (S = 64..600) take about 260*S^2 steps. Their zone pieces depend on the parity of m (S = 200/202/204 vs 201/203 differ in shape). This extrapolates to about 1e16 steps at the real sizes. rebuild_split.txt
  • sim After a capped rebuild (S = 512): 2e10 more steps, no halt, and a fresh base-4 counter grows from a new wall. rebuild_continue_S512.txt
  • sim No halt to 2e10 steps by direct simulation. The left edge stayed at -78 from step 1.8e8 until the overflow.
decision.json: 8 warnings
  • rationale: about 11 lines (contract: <= 3)
  • evidence[0].kind: 'validation' is not one of figure, fact, link (shown as a fact, tagged 'validation')
  • evidence[1].kind: 'sim' is not one of figure, fact, link (shown as a fact, tagged 'sim')
  • evidence[2].kind: 'analysis' is not one of figure, fact, link (shown as a fact, tagged 'analysis')
  • evidence[3].kind: 'risk' is not one of figure, fact, link (shown as a fact, tagged 'risk')
  • evidence[4].kind: 'sim' is not one of figure, fact, link (shown as a fact, tagged 'sim')
  • evidence[5].kind: 'sim' is not one of figure, fact, link (shown as a fact, tagged 'sim')
  • evidence: 7 items (contract: <= 4; the extra ones are folded)

check: python3 -B tools/decisions.py --lint '1RB1RF_1RC---_1RD0RD_1LE1RC_1RA1LE_1RE0LF'

space-time diagram from the blank tape, steps 0 to 10,000
1RB1LE_0RC1RC_0RD0RB_1RE0RF_1LA0LE_---1RB#20sheet Chaotic Fractal Type 1 ≠ ours Fractal call-stack bouncer (FractalType7/TM20 shape) · med confidence
▲Stuckdeepen2asked Oct 10pagedecision.jsonbbchallenge ↗

Why it is here STUCK at deepen2 with mechanism confidence med. Two rounds of hand rule-closure did not converge, and status.json asks for your call: abstract simulator, decider search, or park.

Park #20 (it stays STUCK), or fund one more stage to build an abstract run-length simulator that generates its full call-stack rule table?

✓ you said park · Park: keep STUCK, no more agent time now · Oct 10
“Dennis: go with all recommendations (2026-10-10)”

Options

Effort if yes None now: 0 agent hours and 0 processes. Status stays STUCK, with a re-entry note.

Why Claude recommends park

The architecture is TM20's call stack, but the hand closure is spreading rather than converging. Round 2 added 10 rules (731/731 instances pass) and still found 2 parsed and 7 transit classes that first appear in epoch 7. It also found a root that drifts right, which TM20's fixed-root invariant does not cover. The blocker is not the rule list. It is an invariant grammar that keeps every call away from the halting shapes, and there is no candidate for it. Small configurations next to reachable ones often halt (640 of 1,584); medium ones never do (0 of 144). The real run makes a room-2 call in epoch 7, so a proof must show that small blocks arise only at low recursion levels and in fixed shapes. The observer warns this turns cryptid-like if that fails. mxdys's FractalType7 LLM batch did not solve this machine either. Parking costs nothing and frees budget for machines with validated mechanisms. Revisit if an abstract run-length simulator gets built for another fractal (for example, if #16's accelerated simulator generalises), or if the family sweep finds a solved FractalType7 sibling whose grammar covers transit callees.

Evidence
  • validation Deepen round 2: 10 new rules (Call4, Call2 odd/even, ResumeTY and 3 halting patterns), 731/731 random-context instances. Round-1 rules unchanged. deepen2_validate.txt
  • analysis Census to 1e9: of 46,375 E:R moments, 45,716 parse as standard frames (40 classes) and 659 are transit forms (86 shapes). 2 parsed and 7 transit classes first appear in epoch 7 (step >= 4.58e8). deepen2_census_1e9.txt
  • risk Danger scan with caller X/Y(20,16,5) and 'E> 0^2 1^n 0^2 1^m 0^g 1100 1^5': for small n, m, g, 640 of 1,584 halt, in every residue class. For medium sizes, 0 of 144 halt within 2e7 steps. deepen2_danger_small.txt
  • Fig 1 · State-E entries, to 3 million steps
    Fig 1, state-E entries to 3e6 steps: the replay staircases to the left of each wide white band.Fig 1, state-E entries to 3e6 steps: the replay staircases to the left of each wide white band.
    bbchallenge-defaultStart blankRows every entry into state E moving rightWindow cells -16..4214, 1 px = 1 cellColors 1 0 or unvisited head (last move right/left)
    Rows: 1,937 rows to step 3,000,000 (1,402 at the right edge = right turnarounds, 535 inside the tape), 9 to 5,473 steps apart · Colors: (10)^b blocks are 1-px stripes that look gray when shrunk, 1^a blocks are solid white
3 more items (past the contract's 4)
  • sim The real run makes a room-2 call in epoch 7 (step 458,654,411). Shifting its block sizes by -6..+6 (36 runs) never halts within 5e8 steps. deepen2_perturb.txt
  • sim No halt to 1e9 steps (C core) or to 1.99e13 steps (qsim). Span grows like sqrt(5.6 t). notes.md
  • doc Deepen-2 summary, remaining gaps and the three ways to unstick it. deepen.json
decision.json: 8 warnings
  • rationale: about 11 lines (contract: <= 3)
  • evidence[0].kind: 'validation' is not one of figure, fact, link (shown as a fact, tagged 'validation')
  • evidence[1].kind: 'analysis' is not one of figure, fact, link (shown as a fact, tagged 'analysis')
  • evidence[2].kind: 'risk' is not one of figure, fact, link (shown as a fact, tagged 'risk')
  • evidence[3].kind: 'sim' is not one of figure, fact, link (shown as a fact, tagged 'sim')
  • evidence[4].kind: 'sim' is not one of figure, fact, link (shown as a fact, tagged 'sim')
  • evidence[6].kind: 'doc' is not one of figure, fact, link (shown as a fact, tagged 'doc')
  • evidence: 7 items (contract: <= 4; the extra ones are folded)

check: python3 -B tools/decisions.py --lint '1RB1LE_0RC1RC_0RD0RB_1RE0RF_1LA0LE_---1RB'

space-time diagram from the blank tape, steps 0 to 10,000

Why it is here STUCK after two funded stages (pass 2 and the pass-3 review fix). The rest is new mathematics beyond the stage budget, so continuing needs Dennis's call.

Fund one more stage (at most 2 h) to prove Lemma T and find the shape condition K that closes twin #2's domain, or park it as STUCK?

✓ you said park · Park as STUCK · Oct 10
“auto-applied: Claude's recommendation, under Dennis's standing instruction 'do your recommendations and continuously orchestrate' (2026-10-10, while he was at lunch). Override any time.”

Options

Effort if yes One stage, at most 2 h, light compute (pure-Python closure tests, one niced process). Formalization afterwards: several stages.

Why Claude recommends park

Rules, sweep and start compile; the domain is one inequality, and V* makes the sweep affine. Missing: a proof of Lemma T and a condition K on L positions. Both are new math, and so is the Rocq port. Park unless the queue runs dry: one kill for several stages of new work.

Evidence
  • J4 := ends with 1 and V* <= 2N+1 fails at (257, 10000000L1): V*(x') = 642 > 519, yet theta(x') = 94 <= N' (check 9i). proof.md
  • 400 random J4 starts x 25 sweeps: theta <= N at every step; V*/N falls below about 1.45 after two sweeps (check 9j). check_proof.py
  • Without the new RIncs_eq, 75 of 15,593 G words have no derivation. With it all do, and Example sweep_LS01 compiles (5/5 closed). TwinSpec.v
space-time diagram from the blank tape, steps 0 to 10,000
1RB1RA_1LC1RE_---0LD_1LE1LD_0RA0LF_1LF0LB#26Bouncer + Chaotic Edge (sheet) · ours adds: exact mirror twin of #5 (same edge, same open erosion bound) · med confidence
⚠Cryptid candidateobservingasked Oct 10pagedecision.jsonbbchallenge ↗

Why it is here Medium confidence at observe: the mechanism is exact (mirror twin of #5), but there is no non-halting argument, because the shared edge has no known erosion bound. Proof work waits on Dennis.

#26 is #5 mirrored with renamed states (same edge at every bounce): park it with #5 as one cryptid candidate, or fund the shared Rocq rule reduction now?

✓ you said park_with_5 · Park with #5 as one cryptid candidate · Oct 10
“auto-applied: Claude's recommendation, under Dennis's standing instruction 'do your recommendations and continuously orchestrate' (2026-10-10, while he was at lunch). Override any time.”

Options

Effort if yes park_with_5: none. pair_reduction: one stage (at most 2 h), new file without a nonhalt claim. erosion_research: open-ended, likely several stages with a low chance.

Why Claude recommends park_with_5

Tables identical under mirror + renaming; edges agree at all 102,240 bounces to 1e10. So #5's 2026-10-10 cryptid call applies unchanged: no known erosion bound. The owed rule reduction is best done once, in one file for both twins.

Evidence
  • Fig 2 · #26 beside its twin #5, mirrored
    Fig 2: #26 beside #5 mirrored, one row per bounce; red marks the only differing cell (the wall).Fig 2: #26 beside #5 mirrored, one row per bounce; red marks the only differing cell (the wall).
    customStart blankRows one row per bounceWindow cells -201..192, 1 px = 1 cellColors 1 0 cell where the two tapes differ gap between the panels
    Rows: bounces 1..200: left panel = each new left record of #26, right panel = each new right record of #5 · Window: #26 cells; right panel: #5 cell x drawn at column -x-1, i.e. mirrored and shifted 1 cell · Colors: no head drawn
  • Twin map: #26 at 0^inf <E 1^n w 0^inf (step t) <-> #5 at 0^inf rev(w) 1^(n+1) B> 0^inf (step t+2k), k = 2..102,241, 102,240/102,240. lockstep_1e10.txt
  • Rules: walks, bounce, T/Ca/Fo/E1/E2/P1/P2 and the halting door, 60/60 each; no-00 invariant 0 violations to 1e9. validate_rules.json
space-time diagram from the blank tape, steps 0 to 10,000
1RB0RA_1LC0LD_1LE1LD_0LB0RE_1RF1LB_---0RA#28Bell eats counter (sheet) · ours adds: BECv1 tm10 with E1 = 1LB (3-cell binary counter with fillers + unary marker; eats shift the counter) · med confidence
⚠Cryptid candidateprove l9 (L9 open; flagged cryptid with #10)asked Oct 11pageproof.mddecision.jsonbbchallenge ↗

Why it is here Cryptid flag after the funded prove_l9 stage: L9 cannot close by a local invariant, and #28 turns out to be #10 (already a cryptid candidate) mirrored and started in E, with the same orbit from epoch 350,328 on. A priority call.

#28 is #10 mirrored and started in E, and the two orbits merge: park it with #10 as one cryptid candidate, fund the shared Rocq rule reduction now, or fund research on the shared Lemma X?

✓ you said park_with_10 · Park with #10 as one cryptid candidate · Oct 12
“Dennis: apply recommendations (2026-10-12)”

Options

Effort if yes park_with_10: none. joint_reduction: one stage (at most 2 h), a new file with no nonhalt claim. lemma_x_research: open-ended, likely several stages with a low chance of success.

Why Claude recommends park_with_10

Same table under mirror + renaming; the orbits coincide from our epoch 350,328. #10's counter-family satisfies #28's full invariant, then reaches an unsafe eat. L9 is proved except one exact-carry case: #10's open Lemma X, so its call applies.

Evidence
  • Conjugacy: A..F -> E,A,B,F,C,D mirrored, 12/12 entries, 3,000,000 steps lock-step; merge: our epoch 350,328 = #10's cascade state at t = 350,272 conj10.json
  • #10's family sigma0(B) in #28's rules: invariant holds, L9 then fails twice, and the third flush is late (an eat sees an s block), for every B = 8..18 family10.json
  • Real machine at B = 8: 779/779 round starts match, the unsafe eat comes at N = 194, then the machine recovers (no halt in 2.8e6 steps) tm_family_B8.json
  • Debris lemmas W1-W5 (L9 everywhere but case H): 100,000 random states, 0 violations; in case H, 1,836 of 34,699 successors exceed s = 1 l9_reduce.json
space-time diagram from the blank tape, steps 0 to 10,000
1RB0LF_1LC0LA_---1RD_1RF1RE_1LF1RD_1LB0RE#35Bouncer + Chaotic Edge (sheet) · ours adds: period-10 bulk on a left wall, 7-bounce junction, chaotic edge identical to #13's · low confidence
▲Stuckobservingasked Oct 10pagedecision.jsonbbchallenge ↗

Why it is here Low confidence at observe: the bouncer and junction are exact, but non-halting rests on a chaotic edge map, and that edge is #13's edge, which was parked.

#35's chaotic edge is cell for cell #13's parked edge: park #35 with #13, or fund a shared stage on that edge?

✓ you said park_with_13 · Park with #13: mark STUCK at observe and link the two · Oct 10
“auto-applied: Claude's recommendation, under Dennis's standing instruction 'do your recommendations and continuously orchestrate' (2026-10-10, while he was at lunch). Override any time.”

Options

Effort if yes park_with_13: none. shared_edge: about 2 h, low odds. reduction: about 1 stage.

Why Claude recommends park_with_13

The only open part is the edge map; #13's tail = fixed 58-cell word + our Z at 1,952/1,952 visits. #13 was parked on exactly this edge, and 5e6 more visits here show nothing new (no repeat, no halt). Everything else is exact: wall, sweeps, junction bounces 360/360, edge visit n-free 2,077/2,077.

Evidence
  • Fig 3 · Bulk, junction and edge, every 28 bounces
    Fig 3: bulk and junction columns stay fixed; all disorder is in the edge bandFig 3: bulk and junction columns stay fixed; all disorder is in the edge band
    customStart blankRows every 28 bouncesWindow cells -60..539, 1 px = 1 cellColors 1 0 right of the visited span
    Rows: (every 4th edge visit), bounces 315..14,819 of the 1e9-step run, 519 rows, each taken at a left record · Window: cells counted from the junction frame, which moves 12 cells right per row (3 per edge visit)
  • #13's tail at bounce c-6 = fixed 58-cell word + #35's Z at bounce c, 1,952/1,952 edge visits notes.md
  • Edge map iterated 5e6 visits (~5e15 machine steps): |Z| 143-563, no exact repeat, no halt phi2_5e6.txt
space-time diagram from the blank tape, steps 0 to 10,000
1RB1RF_1LC0RF_1LE0LD_1RC0LB_---1RA_1LB1RA#36Bouncer + Chaotic Edge (sheet) · ours adds: twin of #13 at the cycle level (same bulk, junction and tail orbit D_n) · med confidence
▲Stuckobservingasked Oct 10pagedecision.jsonbbchallenge ↗

Why it is here Low/med confidence at observe: the mechanism is exact, but it reduces to #13's open edge lemma (E'), which Dennis parked on #13. Proof work waits.

Park this machine with #13 (same edge lemma), or fund one family stage on that lemma for #13, #34, #35 and #36?

✓ you said park · Park with #13: STUCK at observe, keep the card and rules as the reduction · Oct 10
“auto-applied: Claude's recommendation, under Dennis's standing instruction 'do your recommendations and continuously orchestrate' (2026-10-10, while he was at lunch). Override any time.”

Options

Effort if yes park: 0. family: 2 h agent time, odds low. halt_search: about 1 core-hour of background CPU, no agent time.

Why Claude recommends park

Not easier than #13: same junction, same tail cycle for cycle, same probe map on every tested input. You parked #13 on this lemma; this machine gives no new idea for (E'). New value: any future (E') proof now pays 4 kills (noted here and in STATUS.md).

Evidence
  • Fig 2 · Our tail vs #13's tail, per cycle
    Fig 2: our tail D_n | #13's tail | XOR, one row per cycle (XOR all black)Fig 2: our tail D_n | #13's tail | XOR, one row per cycle (XOR all black)
    customStart mid-run: step 679,041Rows one row per 7-bounce cycle n = 0..399Window cells 0..423, 1 px = 1 cellColors 1 0 past the end of D same cell cells differ
    Start: row 0 = cycle start C_0(58, D_0) of the run from blank; #13's row 0 is its C_0(59, D_0) at step 784,041 · Rows: taken at each cycle start (this machine: steps 679,041..47,105,452) · Window: of D in each of 3 panels (cell 0 = first cell right of the 54-cell junction X0); panels: this machine | #13 | XOR · Colors: blue-grey bar = panel separator; XOR panel
  • Probe map equal to #13's: 120/120 orbit D; 200 random D give 97 the same and 103 break in both; 0 disagree validate.json
  • #35 is this table renamed (A..F -> D,C,E,A,F,B) and follows the same D_n; #34 follows the mirror of D_n notes.md
  • Edge map clean to 1.5e7 cycles (about 4.9e16 real steps); its first 5.5e6 cycles match #13's log line for line edgemap_5.5e6_to_1.5e7.txt
space-time diagram from the blank tape, steps 0 to 10,000
1RB0LF_1RC1RB_0RD0RC_1LE1LF_1LD---_0LB1LA#37Sync bouncer counter (sheet) · ours adds: binary counter on the left, eroding 1-block timer on the right, doubling reset · med confidence
▲Stucktwin port refutedasked Oct 10pagedecision.jsonbbchallenge ↗

Why it is here Priority call: the follow stage found no halt to phase 1,857 and predicts the next excursion (phase 3,321) benign. A proof would need a grammar for the merge wave, with no template close.

#37 stays in sync to phase 1,857, and its next excursion (phase 3,321) is predicted benign: park it, spend one round deriving the merge-wave rule, or first confirm phase 3,321 on the real orbit?

✓ you said park · Park #37 behind the other machines · Oct 11
“Dennis: go with recommendations (2026-10-11)”

Options

Effort if yes park: none. grammar: one ~2 h round, light compute, no Rocq. confirm: about 1 h of one light C process from work/follow/ckpt_follow_end.txt, plus ~15 min of agent time.

Why Claude recommends park

No halt to phase 1,857; 4/4 excursions benign; the 3-run in question was absorbed by a merge. Fast-forward is exact on the past excursion and predicts the next 3 excursions benign. A proof needs a wave grammar on unbounded run words; no busycoq template is near.

Evidence
  • Real orbit followed to phase 1,857 (n ~ 2^1860) with the C port: excursions at phases 91, 119, 215 and 487, all benign, with 14, 77, 93 and 700 cells in the run that became the bottom. real2.log
  • C port checks: 160/160 phases equal to Python; random instances 90/90 vs Python and 90/90 vs exact fastphase; fast-path rules 3,000/3,000 each. cmp_c_vs_py_160.log
  • Fast-forward from phases 311 and 411 reproduces the real excursion at phase 487 and its cascade (45/45 phases). From phases 811, 1,011 and 1,207 it predicts phase 3,321 as benign, with a1 = 555. next_d1196_r4.txt
  • Fig 5: frozen runs are vertical stripes, merge waves are diagonal bands, and short runs (orange) are absorbed by the next wave. follow_lowruns_real.png
space-time diagram from the blank tape, steps 0 to 10,000
1RB0RA_1LC0LF_1LE0LD_1LB---_1RA1LB_0LD0RCR2Bell eats counter (sheet) · ours adds: tm108-like 110/010 bell eats a 3-cell-digit binary counter; eat size varies (not BECv1) · low confidence
▲Stucksize invariantasked Oct 10pagedecision.jsonbbchallenge ↗

Why it is here STUCK at the size-invariant stage, confidence med: non-halting now rests on one inequality (R1: T_k + 1 <= I_k), but no inductive proof of it was found.

R2's size invariant is reduced to one inequality that needs a crossing lemma near powers of two: park R2 until #29/R3's size-invariant stages report, fund an R2 crossing-lemma stage now, or park it for good?

✓ you said wait_shared · Park until #29 / R3 report on the same lemma · Oct 10
“auto-applied: Claude's recommendation, under Dennis's standing instruction 'do your recommendations and continuously orchestrate' (2026-10-10, while he was away). Override any time.”

Options

Effort if yes wait_shared: none now, a short port stage later. crossing: one stage, at most 2 h, pure Python, one niced process, no Coq.

Why Claude recommends wait_shared

One inequality is open: R1 holds at all 808,539 epochs to N = 1e7 (T/I <= 0.13 for N >= 2^14). Size-only invariants are not inductive, so a crossing argument is needed. #29 and R3 face the same lemma now; waiting costs nothing.

Evidence
  • Gaps never grow (20.6M ball-eats to N = 1e7, 743k random); births outside one special case satisfy 2^h1 <= V*/2; R1 holds at every epoch firstt_1e7.txt
  • R1 margin per octave of N to 1e7: T/I <= 0.28 (2^13 octave), <= 0.13 for N >= 2^14 binned_1e7.txt
  • Near-power-of-two random states break the size-only candidates Ja/Jb/Jc (44/601/668 of 2000 within 3 epochs) randinv2_2.txt
  • Fig 2 · Rounds aligned at the bell boundary
    Fig 2: rounds aligned at the bell boundary; each triangle is an epochFig 2: rounds aligned at the bell boundary; each triangle is an epoch
    customStart blankRows one row per clean round startWindow cells -80..-1, 1 px = 0.33 cellsColors 1 0 (left word L) never visited boundary cell b (a 1) one 110 block one 010 block beyond the tape
    Rows: (E0 -> A turn landing on the boundary cell b of 1 (110)^e (010)^f 1), i.e. every second round of an epoch: 198 rows, steps 250,017..469,936 · Window: (3x scale), counted from the boundary cell b; then b (red); then 112 columns in block units (1 column = one 3-cell block) · Colors: black right of
space-time diagram from the blank tape, steps 0 to 10,000
1RB0RF_1RC0RE_1LD1RA_1LA0LD_1RA---_0RA0LBR3Bell eats counter (sheet) · ours adds: FractalBEC-like 101/00 bouncer plus a 3-cell binary counter with transparent J blocks; the bell shifts the counter one cell · med confidence
▲Stuckcrossingasked Oct 10pagedecision.jsonbbchallenge ↗

Why it is here Med confidence after the crossing stage, whose stop rule fired. Non-halting now rests on one rare-event lemma (Big-Y) with no inductive proof.

The crossing stage hit its stop rule (Lemma S proven, the Big-Y lemma open, with 3 instances in 1e7 epochs): park R3 with R2, fund one Big-Y stage, or start Rocq with Big-Y as the one hypothesis?

✓ you said park · Park R3 with R2 (stop rule) · Oct 11
“Dennis: go with recommendations (2026-10-11)”

Options

Effort if yes Park: none. Big-Y: about 2 h of agent time, native, no Coq search. Rocq: several stages.

Why Claude recommends park

Stop rule fired: no inductive form for C or C0; C0 breaks on random near-crossing states. Narrower gap than L*: Lemma S covers every epoch with Y < 2^(m+1); the rest occurs 3 times in 1e7. Big-Y has a concrete target, but it is the same crossing arithmetic that stalled R2.

Evidence
  • Fig 2 · Hub rows: gap and counter, four epochs
    Hub rows: gap and counter over four epochsHub rows: gap and counter over four epochs
    customStart mid-run: step 2,850,432Rows one row per K hubWindow cells 1..90, 1 px = 0.33 cellsColors digit 1 (010) digit 0 (000) J block (100) x/z/w block (001/011/101) past the end of G 101 blocks the 00 gap
    Rows: (one bounce), 943 hubs from step 2,850,432 to 3,848,095 · Window: (counted right of the head, 9 px per 3-cell group); left 120 px = gap position a/(a+b) · Colors: left panel; cyan bar between panels = a b=0 hub
  • Integer model to 1e7 epochs (N = 1.44e8): all safe, but the minimum margin is 1.000 bit (epoch 350,274, N = 2^22 - 4,693), not 2.3. longrun_1e7.txt
  • Lemma S (C(e) => next epoch safe): 100,000/100,000 trajectory epochs and 59,887/59,887 random states. lemma_s_checks.txt
  • Big-Y epochs (Y >= 2^(m+1)) to 1e7: only 9, 16 and 350,275, each right after a Y = 2^m pair; C-margins 3, 3, 15. crossing_stats_1e7.txt
space-time diagram from the blank tape, steps 0 to 10,000
1RB0RA_1RC1RF_1LD0LC_1RA1LE_1RA0LC_---0RDR8sheet Unknown ≠ ours Sync bouncer counter (SBCv8 TM31 cousin): binary counter left, ternary throttle right, nested overflow pause · low confidence
▲Stuckf3 firstasked Oct 11pageproof.mddecision.jsonbbchallenge ↗

Why it is here Stuck after f3_first: the overflow bursts open an unbounded tower of throttle levels, and some inputs the deeper levels can receive make zone T halt. A priority call is needed.

Park R8, spend one research stage on the tower (the safe input language of a level plus a burst-timing lemma), or flag it as a cryptid candidate?

✓ you said park · Park · Oct 12
“Dennis: apply recommendations (2026-10-12)”

Options

Effort if yes tower_stage: one 2 h stage of light native compute (finite-automaton search plus simulations). park and cryptid_flag: none.

Why Claude recommends park

BR is an exact M-type word; its gliders build K = 3 levels without end (33/33). Zone T halts on B^1 or B^3 bursts with short gaps, and deeper levels can get B^3. Excluding that needs control of pseudo-random burst timing (about 2^-m per epoch).

Evidence
  • Fig 3 · The m=14 overflow: creep across the middle
    Fig 3: the m = 14 creep. The glider leaves the middle as five B visits; a BR glider does the same at the far end and builds a new level.Fig 3: the m = 14 creep. The glider leaves the middle as five B visits; a BR glider does the same at the far end and builds a new level.
    bbchallenge-defaultStart mid-run: step 148,740,000Rows every 250 stepsWindow cells -100..699, 1 px = 1 cellColors 1 0 or unvisited head moving R/L
    Rows: steps 148,740,000..148,890,000 (601 rows) · Window: absolute positions
  • B^j A^n with j up to 991,164: 0 halts in 300 runs; 48 runs built a second level with K = 3. bigburst_small_e_seed11.jsonl
  • Zone T halts: T(RP; 34) on B3 A4 B3 B3 A6 B3 A4 B3 (2/200 for B^3, 15/200 for B^1). multiburst_bs.txt
space-time diagram from the blank tape, steps 0 to 10,000
1RB1RF_1LC0RB_1RD0LC_1LE1RA_0RC1LB_---1RER9sheet Unknown ≠ ours Nested binary counters of toggling defect walls in a period-5 sea, with engine-dissolving epochs (multi-region) · low confidence
▲Stuckobservingasked Oct 10pagedecision.jsonbbchallenge ↗

Why it is here Low confidence at observe: the global epoch/bit-creation law is unknown, so proof work waits for a priority call.

Spend one more stage on the epoch/bit-creation law (wall catalogue plus an abstract wall simulator), or park R9 as STUCK at observe?

✓ you said park_sim · Park as STUCK at observe, plus one niced background run to 1e12 as a cheap halt check · Oct 10
“Dennis: go with all recommendations (2026-10-10)”

Options

Effort if yes No agent time beyond launching one niced tools/sim.py run to 1e12 (about 70 min, under ulimit -v 6000000) and checking its result once when it ends. Status becomes STUCK (observe).

Why Claude recommends park_sim

Only the bottom level is understood. The sea sweeps, the wall toggles and both inner counter laws are exact (33,140/33,140 and 5,545/5,545 turns on the orbit). Above that level there are several unknowns: a second engine/counter pair, edge structures, engine-dissolving epochs (43 between 1e9 and 2.73e9, then none in the inner region), and a regime change at about 2.7e9 that 1e10 steps may not fully show. The defect algebra has real halting routes (B> 1^n 0 1 0, or a D sweep meeting 110), so non-halting needs a global invariant on defect shapes. qsim does not accelerate it and no template applies. Edge visits keep slowing (near 8e9 the left edge is visited about once per 1.5e9 steps), so each new regime costs more simulation. One stage is unlikely to make this machine proof-ready, while other machines are one stage away from proof work. The 1e12 run costs almost nothing and is the one cheap way to learn something new.

Evidence
  • rules 7 exact local rules at 200/200 each (S_R, S_L, RB0, RB1, RB1r, LB0, D_R) and the halt pattern H at 400/400. The inner counter laws hold on the orbit: 33,140/33,140 (right) and 5,545/5,545 (left). notes.md
  • open Not understood: the right-end engine/counter pair, the edge structures, and the engine-dissolving epochs (EP has no exact rule). The regime changed at about 2.73e9. observe.json
  • Fig 3 · Where the head turns, log time to 1e9
    Card Fig 3: where the head turns, log time to 1e9 (several separate wall systems).Card Fig 3: where the head turns, log time to 1e9 (several separate wall systems).
    customStart blankRows 800 log-spaced time bins from step 1e3Window cells -549..988, 1 px = 1 cellColors no turn right turning point (R -> L) left turning point (L -> R)
    Rows: (top) to 1e9 (bottom); a turning point is a sweep's extreme cell before the head moves 8+ cells back · Colors: dark = both; darker = more turns in the bin (log scale)
  • Fig 1 · Edge records to 10 billion steps
    Card Fig 1: edge records to 10 billion steps.Card Fig 1: edge records to 10 billion steps.
    bbchallenge-defaultStart blankRows the start, then one per new leftmost or rightmost cellWindow cells -729..1291, 1 px = 1 cellColors 1 0 or never visited head at a new right/left edge
    Rows: (2,021 rows, steps 0..9,957,807,009); not evenly spaced in time
2 more items (past the contract's 4)
  • data Edge records to 1e10: +3 cells per edge visit, visits slowing; 2,021 cells at 1e10. records_1e10.jsonl
  • status status.json: CHECKPOINT_A, observe, confidence low, priority_call = one more stage or park. status.json
decision.json: 6 warnings
  • rationale: about 9 lines (contract: <= 3)
  • evidence[0].kind: 'rules' is not one of figure, fact, link (shown as a fact, tagged 'rules')
  • evidence[1].kind: 'open' is not one of figure, fact, link (shown as a fact, tagged 'open')
  • evidence[2].kind: 'data' is not one of figure, fact, link (shown as a fact, tagged 'data')
  • evidence[5].kind: 'status' is not one of figure, fact, link (shown as a fact, tagged 'status')
  • evidence: 6 items (contract: <= 4; the extra ones are folded)

check: python3 -B tools/decisions.py --lint '1RB1RF_1LC0RB_1RD0LC_1LE1RA_0RC1LB_---1RE'

space-time diagram from the blank tape, steps 0 to 10,000
1RB0LA_1RC---_0LD1RD_0RA0RE_0RF1RC_1LF0LAW7-6sheet Translated Counter ≠ ours Translated base-4 counter with overflow, trail erase and nested rebuild (phase cycle) · med confidence
⚠Cryptid candidatewave7-stage1asked Oct 14pagedecision.jsonbbchallenge ↗

Why it is here W7-6 stage 1 ended by its stop rule (cryptid-like halting condition); any stage 2 needs a new decision.

Park line 33 as a cryptid-like translated counter, or fund one 2 h stage to build the exact phase model and decide the transition at ~4.6e15 steps?

✓ you said park · Park as cryptid candidate · Oct 16

Options

Effort if yes One 2 h stage (Python/C, no Coq). A HALT result would need a further formal stage.

Why Claude recommends park

Counting is exact and safe; halts need an exact value/gap coincidence at overflow/collision events. The orbit survived every event to 2.1e7; the next event is ~4.6e15 steps out and hinges on irregular digits. Even a halt there needs a W5-5-style formal increment lemma and runner: kill odds about 0.05.

Evidence
  • Fig 1 · Phases to 2.2e7: count, erase, rebuild
    Phases to 2.2e7: count, erase, rebuildPhases to 2.2e7: count, erase, rebuild
    bbchallenge-defaultStart blankRows every 20,000 steps (1101 rows, to step 2.2e7)Window cells -81..89,280, 1 px = 128 cellsColors 1 0
    Colors: black: each pixel samples one of 128 cells
  • Fig 3 · A collision that halts
    A synthetic collision that haltsA synthetic collision that halts
    bbchallenge-defaultStart constructed tape (below)Rows every 8 steps; last row = halt at step 6290Window cells -90..47, 1 px = 1 cellColors 1 0
    Start: 0∞ 13 0 12 0 15 0 130 02 13 0 12 0 12 0 13 0 12 0 12 0 1 C> 028 1 0∞ · Colors: coloured pixel = head (bbchallenge colours)
  • R1: each C right record = +1 on the base-4 pair counter, 10,416/10,416 random transitions. validate_increment.py
  • Current counter: 23 pairs, V = 61,170,343,443,693 at step 100,000,903; ~9.2e12 increments (~4.6e15 steps) to overflow. notes.md
space-time diagram from the blank tape, steps 0 to 10,000
1RB1RA_1LC0RE_1LE0LD_0LB1LB_1RA0LF_1LD---W4-8sheet Unknown ≠ ours Fossil bouncer: one bounce per cycle over a sea of u = 01001111 with seams; the wall leaves 1-deposits that later fossilize · low confidence
▲Stuckseamsasked Oct 11pagedecision.jsonbbchallenge ↗

Why it is here The funded seams stage hit its stop rule (seam alphabet still growing at 1e10), so W4-8 is parked. New evidence suggests a different route might work, and only you can fund it.

Keep W4-8 parked, or fund one 2 h native search for a closed tape language that only has to forbid 00 <B inside the tape?

✓ you said park · Keep parked (STUCK) · Oct 12
“Dennis: apply recommendations (2026-10-12)”

Options

Effort if yes One stage (about 2 h) of native search. If a closed language is found: a CTL-style Coq check of that certificate (about 1-2 stages), which covers 61 and 704 if the language contains their orbits.

Why Claude recommends park

Seam words keep growing at every abstraction (1,028 verbatim, 270 pieces at 1e10); no template is near. Yet re-drawn run lengths never halt (0/1,200): one local invariant (no 00 <B inside) would suffice. Standard CTL/NG deciders already missed this holdout, so a 2 h search has only a fair chance.

Evidence
space-time diagram from the blank tape, steps 0 to 10,000
1RB1RC_1LC1LE_1RD0RA_1LB0RA_0LD1LF_1LD---W7-1sheet Skelet 1-like Class 1 ≠ ours Skelet 1-like: binary counter whose digits are field parities, with re-pairing bounces · high confidence
▲Stuckinformal proofasked Oct 14pageproof.mddecision.jsonbbchallenge ↗

Why it is here Cryptid-protocol stop: proof.md revision 2 fixed the two major gaps, but O1 (no inductive invariant) hinges on a far-end race decided by history-dependent parities.

W7-1 (lines 75/597/265/179): park it as cryptid-like, or fund a bounded 2 h halting search with the exact fast map toward 10^1000 steps?

✓ you said halt-search · Bounded halting search (2 h) · Oct 16

Options

Effort if yes At most 2 h wall time, 2 processes, nice 10; output: a far-end history per start and, if found, the exact halting configuration.

Why Claude recommends halt-search

No outside case to 1e100 on the four starts, but perturbed copies fail at the far end (~0.2 % per episode). Some failures halt (+ 0 +); the exact fast map reaches 1e100 in ~2 s, so a halting search is cheap.

Evidence
  • proof.md revision 2, section 6.4: far-end race; 24/300 perturbations of line 75 at 1e13 leave the rule set (22 at the far end, 3 at the halting + 0 +), between 1e14 and 1e85 steps. proof.md
  • check_proof.py PASS (A-I): 15 rules, climb automaton, both C6 branches; fast map = plain map to 1e11; no outside case to 1e100 on all four starts. check_proof.out
  • The race (check_proof.py section C): 1 + 0 | 0 | 23 | 86 | 300 | L stays inside the rules for L = 1201 but meets (o4) for L = 1200; the far region's direction decides. check_proof.out
space-time diagram from the blank tape, steps 0 to 10,000
1RB1LD_1LC0RF_0RD0LB_1LB0LE_1LA---_0RA0RF740 line 6sheet Bouncer + Chaotic Edge ≠ ours Period-seven bouncer with partially described edge returns · med confidence
–Skippeddeferredasked Oct 14pagedecision.jsonbbchallenge ↗

Why it is here The approved 30-minute study is complete. The full mechanism still has low/medium confidence; further research is a new priority call.

Defer 6/348, or fund another 30-minute study of the variable edge-word transformation?

✓ you said defer · Defer further research · Oct 14

Options

Effort if yes At most 30 minutes. This is a new stage; no whole-machine formalization is funded.

Why Claude recommends defer

One general return is derived, but the other two remain candidates and the edge-word family is not closed. Line 593 has a more sharply isolated safety condition.

Evidence
space-time diagram from the blank tape, steps 0 to 10,000
1RB0LD_1RC0RD_1LA0RC_1RE1LB_1LF0LA_---0LE740 line 282sheet Bouncer + Chaotic Edge ≠ ours Bouncer with unresolved word dynamics · low confidence
–Skippeddeferredasked Oct 14pagedecision.jsonbbchallenge ↗

Why it is here The approved 30-minute study is complete. The full mechanism still has low/medium confidence; further research is a new priority call.

Defer line 282, or fund a 30-minute study of its nonlocal word grammar and endpoint phases?

✓ you said defer · Defer further research · Oct 14

Options

Effort if yes At most 30 minutes. This is a new stage; no whole-machine formalization is funded.

Why Claude recommends defer

Two exact return families are derived, but short-factor and modulo-six endpoint languages fail closure. A new nonlocal grammar is needed before formalization.

Evidence
space-time diagram from the blank tape, steps 0 to 10,000
1RB1LD_1RC0RC_1LD0RE_0LB0LA_0RF1LA_---1RC740 line 465sheet Bouncer + Chaotic Edge ≠ ours Bouncer with unresolved word dynamics · low confidence
–Skippeddeferredasked Oct 14pagedecision.jsonbbchallenge ↗

Why it is here Initial observation finished with low or medium confidence in the complete mechanism; further mechanism/proof work waits under CLAUDE.md.

Defer line 465 behind line 282, or fund a 30-minute return-model study?

✓ you said defer · Defer this family · Oct 14
“Follow your recommendations for the 5”

Options

Effort if yes At most 30 minutes for this family; no formal proof stage funded by this decision.

Why Claude recommends defer

The 21-step local extension is known, but the enabling returns remain irregular and sampled factor diversity grows. Line 282 offers a clearer initial lead.

Evidence
space-time diagram from the blank tape, steps 0 to 10,000
1RB0RC_1LC0RB_1LD0LD_1RA1LE_---0LF_1LB1LF740 line 715sheet Bouncer + Chaotic Edge ≠ ours Bouncer with period-20 bulk and unresolved irregular boundary · low confidence
–Skippeddeferredasked Oct 14pagedecision.jsonbbchallenge ↗

Why it is here Initial observation finished with low or medium confidence in the complete mechanism; further mechanism/proof work waits under CLAUDE.md.

Defer line 715 behind line 593, or fund a 30-minute irregular-region study?

✓ you said defer · Defer this family · Oct 14
“Follow your recommendations for the 5”

Options

Effort if yes At most 30 minutes for this family; no formal proof stage funded by this decision.

Why Claude recommends defer

The irregular region grows while the compressor needs 104, 267 and 866 tokens at the sampled horizons. Line 593 gives a more compact starting point.

Evidence
built 2026-10-16 13:29 by python3 -B tools/decisions.py from 24 machines/*/decision.json files (contract: tools/README-decisions.md); 7 with contract problems (listed on the card). Status chips are the live status.json; thumbnails are the dashboard's (bbchallenge.org Default view, start blank, steps 0 → 10,000, cells −200..199).
0 open calls